The domain of a function is the set of all valid inputs. So you think about what can't go in the function and then say everything but. In the case of a square root, you can't take the square root of a negative number. So think about 6 – x is less than 0. So x would be greater than 6. So the domain is what can go in the fucntion, that is, evernthing less than or equal to 6. In the case of a rational function, you can't have a zero denominator. So set the denomnator equal to zero and solve. Then the domain is everything except that.
When analyzing an equation to find its domain, you have to find impossible situations, for example: dividing by zero. square roots of negative numbers, logarithms of zero or negative numbers, etc.
The domain cannot contain any values for which the equation becomes impossible.
March 11th, 2008 at 7:19 am
By eliminating invalid x values.
For f(x) = √(6-x), x ≥ 6, otherwise you're taking the square root of a negative number.
March 11th, 2008 at 7:19 am
The domain of a function is the set of all valid inputs. So you think about what can't go in the function and then say everything but.
In the case of a square root, you can't take the square root of a negative number. So think about 6 – x is less than 0. So x would be greater than 6. So the domain is what can go in the fucntion, that is, evernthing less than or equal to 6.
In the case of a rational function, you can't have a zero denominator. So set the denomnator equal to zero and solve. Then the domain is everything except that.
March 11th, 2008 at 7:19 am
f(x) = sqrt(6-x)
Think of x as the input; then f(x) is the output.
Domain = what you are allowed to use as input.
Range = what values can be reached by the output.
When analyzing an equation to find its domain, you have to find impossible situations, for example:
dividing by zero.
square roots of negative numbers,
logarithms of zero or negative numbers,
etc.
The domain cannot contain any values for which the equation becomes impossible.
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