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1. Dsquared Says:
   March 11th, 2008 at 7:19 am

   Assuming the denominator is x^2 + 3x -4 = (x+4)(x-1), then the domain for f is R\{-4,1}, i.e. f is defined for all real numbers except at x=-4 and x=1.

2. SammyD Says:
   March 11th, 2008 at 7:19 am

   The domain of a function f(x) is the set of all real numbers such that f(x) is real. i.e. in this case all real numbers apart from those which make the denominator (bottom bit) = 0.

   This happens when…

   x^2 + 3x – 4 = 0
   (x-1)(x+4) = 0 [factorising]

   i.e. f(x) is undefined for x = +1, or -4.

   Therefore the domain of f(x) is all real numbers apart from +1 and -4 ( R \ {-4, 1} ).

   sam

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