need hlp with domain and range?
Posted on Mar 12, 2008 under domain news and reports | 6 Commentsgiven:
5/(sqrt(9-x^4)) find the domain and range. Could some show me the steps to find these. thx
given:
5/(sqrt(9-x^4)) find the domain and range. Could some show me the steps to find these. thx
March 12th, 2008 at 7:26 am
Domain is what x equals and range is what y equals… in this problem the denominator cannot equal zero and the value under the square root cannot be negative.
to find the domain set
9 – x^4 >0 and solve for x to get your domain… y depends on x so use this answerr to find out what y will equal
March 12th, 2008 at 7:26 am
I just did this in class.
To find the domain of a radical, set the radical greater than or equal to zero, and that's your domain. If the degree is higher than 2, set it to equal zero.
To find the domain of a rational, set the denominator = to 0 and that number isn't your domain.
You have both. SO:
9-x^4=0
x^4=9 (I multiplied both by -1 so there isn't a neg x)
fourth root both sides.
x= plus or minus fourth root of 9
IDK about the range.
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