Domain And Range f(x,y,z) = Ln(x+y+z-1)?

Posted on Mar 21, 2008 under domain news and reports | 11 Comments

What would the Domain and range be for f(x,y,z)=ln(x+y+z-1)?
Thanks for the help

11 Responses to “Domain And Range f(x,y,z) = Ln(x+y+z-1)?”

  1. notthejake Says:

    domain: x + y + z > 1
    range: (-infinity, infinity)

    the argument of a log function must be > 0; thus, x + y + z – 1 > 0, or x + y + z > 1

    the graph of a log function goes from -infinity to infinity in the y-direction– the range

  2. What does Ln stand for?

    TW K

  3. rangergordon Says:

    The range is (-infinity, infinity) since Ln(a) attains every value in [[R]] for 0 < a < infinity

    However, Ln(a) is undefined for a <= 0. So the domain is such that:

    x + y + z – 1 > 0
    x + y + z > 1, or

    x + y + z is on the interval (1, infinity).

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