Domain And Range f(x,y,z) = Ln(x+y+z-1)?
Posted on Mar 21, 2008 under domain news and reports | 11 CommentsWhat would the Domain and range be for f(x,y,z)=ln(x+y+z-1)?
Thanks for the help
What would the Domain and range be for f(x,y,z)=ln(x+y+z-1)?
Thanks for the help
March 21st, 2008 at 7:07 am
domain: x + y + z > 1
range: (-infinity, infinity)
the argument of a log function must be > 0; thus, x + y + z – 1 > 0, or x + y + z > 1
the graph of a log function goes from -infinity to infinity in the y-direction– the range
March 21st, 2008 at 7:07 am
What does Ln stand for?
TW K
March 21st, 2008 at 7:07 am
The range is (-infinity, infinity) since Ln(a) attains every value in [[R]] for 0 < a < infinity
However, Ln(a) is undefined for a <= 0. So the domain is such that:
x + y + z – 1 > 0
x + y + z > 1, or
x + y + z is on the interval (1, infinity).
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