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1. xopix1 Says:
   April 28th, 2008 at 10:52 am

   c sq. root function as a domain all real
   and adding a no. to it does'nt make a difference
   so y=sq rootx + 3 will also have dom as all real

2. Ron Says:
   April 28th, 2008 at 10:52 am

   If you are dealing only with y as a map from real numbers into real numbers, then note that the square root of a negative number is not a real number.

3. sn777scg Says:
   April 28th, 2008 at 10:52 am

   is the question
   y = √x +3
   or y =√(x+3)where both x and 3 are under the root
   For the first one the domain would be x≥0
   for the second one the domain would be x≥-3

   P.S. The expression under the sqrt cannot be negative.

4. raobn Says:
   April 28th, 2008 at 10:52 am

   When you ask the question please write clearly. Is the square root for x alone or it is for (x+3)? If the sum is y=square root of x + 3, then the domain is x > and = 0. In other case x = -3 and > -3

5. Sir Jekshun Says:
   April 28th, 2008 at 10:52 am

   Real Numbers x and y:

   if y = Sqrt[x+3], then Domain is x > -3.

   if y = Sqrt[x] + 3, then Domain is x > 0.

   For complex numbers x and y,
   where x = a + bi and y = c + di and i = Sqrt[-1]:

   then x can be any complex number. Since all real numbers are elements of the complex numbers, then x can be any real number, as well.

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