State the DOMAIN of this math equation?
Posted on Jun 14, 2008 under domain news and reports | 4 Commentsh(x)=(3/3x(squared)-5x)+7
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June 14th, 2008 at 9:19 am
If the denominator is 3x^2 – 5x, the domain is all real numbers except 0 or 5/3. Those would cause the denominator to equal zero.
June 14th, 2008 at 9:19 am
answer: (-infinity, 0) U (0,5/3) U (5/3, infinity)
Look at the denominator 3x^2-5x. It cannot equal zero or the equation is undefined. So, find the values of x such that 3x^2-5x=0. x turns out to equal 0 and 5/3. Neither of these values can be found in the domain. So, the domain consists of all values besides 0 and 5/3.
June 14th, 2008 at 9:19 am
the domain of a function is whatever set of numbers will solve the equation. This means that any "x" value that will divide by 0 or take the square root of a negative number. So it will be all x except 0 and 5/3. Because it is any number that will solve this equation 0 = 3xsquared – 5x. So if you put this in to the quadratic formula that gives you 5/3 and 0.
January 27th, 2012 at 12:08 pm
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